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NEET BIOLOGYMedium

A gene locus has two alleles A, a. If the frequency of dominant allele A is 0.4, then what will be the frequency of homozygous dominant, heterozygous and homozygous recessive individuals in the population?

A

0.16 (AA); 0.36 (Aa); 0.48 (aa)

B

0.36 (AA); 0.48 (Aa); 0.16 (aa)

C

0.16 (AA); 0.24 (Aa); 0.36 (aa)

D

0.16 (AA); 0.48 (Aa); 0.36 (aa)

Step-by-Step Solution

According to the Hardy-Weinberg principle, the frequency of genotypes is given by the expansion (p + q)² = p² + 2pq + q² = 1, where 'p' is the frequency of allele A and 'q' is the frequency of allele a . Given: Frequency of allele A (p) = 0.4. Therefore, Frequency of allele a (q) = 1 - 0.4 = 0.6.

  • Frequency of Homozygous Dominant (AA) = p² = (0.4)² = 0.16.
  • Frequency of Heterozygous (Aa) = 2pq = 2 × 0.4 × 0.6 = 0.48.
  • Frequency of Homozygous Recessive (aa) = q² = (0.6)² = 0.36.
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