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NEET BiologyMedium

If the distance between two consecutive base pairs is 0.340.34 nm and the total number of base pairs of a DNA double helix in a typical mammalian cell is 6.6×1096.6 \times 10^9 bp, then the length of the DNA is approximately

A

2.0 meters

B

2.5 meters

C

2.2 meters

D

2.7 meters

Step-by-Step Solution

Length of DNA = [0.34×10−9]m×6.6×109bp=2.2m[0.34 \times 10^{-9}] \text{m} \times 6.6 \times 10^9 \text{bp} = 2.2 \text{m}. Distance between 2 base pair in DNA helix = 0.34nm=0.34×10−9m0.34 \text{nm} = 0.34 \times 10^{-9} \text{m}. Total number of base pair = 6.6×109bp6.6 \times 10^9 \text{bp}.

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