The effect of temperature on the rate of reaction is often described by the temperature coefficient. It is a general observation (often cited as a rule of thumb in NCERT) that for a chemical reaction, with a rise in temperature by 10°, the rate constant (and thus the rate) is nearly doubled .

To calculate the final rate increase, we use the formula: $\frac{\text{Rate}_2}{\text{Rate}_1} = (\text{Temperature Coefficient})^{\frac{\Delta T}{10}}$

Given: Temperature Coefficient = 2 (rate doubles) Initial Temperature ($T_1$) = 10 °C Final Temperature ($T_2$) = 100 °C $\Delta T = 100^\circ\text{C} - 10^\circ\text{C} = 90^\circ\text{C}$

Calculation: $\text{Factor} = 2^{(90/10)} = 2^9$ $2^9 = 512$

Thus, the rate of the reaction becomes 512 times the initial rate.