Solved: CHEMISTRY Question for NEET

NEET CHEMISTRYEasy

Which of the following molecule does not possess a $\pi$ bond?

H₂O

SO₂

NO₂

CO₂

Analyze $H_2O$ (Water): The central Oxygen atom is bonded to two Hydrogen atoms via single covalent bonds. Oxygen is $sp^3$ hybridized with two lone pairs and two bond pairs. Single bonds are always sigma ( $\sigma$ ) bonds. There are no multiple bonds, hence no $\pi$ bonds are present.
Analyze $CO_2$ : Structure is $O=C=O$ . Each double bond consists of one $\sigma$ and one $\pi$ bond. Total = 2 $\pi$ bonds.
Analyze $SO_2$ : Structure involves resonance between $O=S-O$ forms. It contains $S=O$ double bond character, implying the presence of a $\pi$ bond.
Analyze $NO_2$ : Structure contains a nitrogen atom double-bonded to an oxygen atom in its resonance hybrid ( $O=N-O^{\cdot}$ ). It possesses a $\pi$ bond.
Conclusion: Only water ( $H_2O$ ) lacks a $\pi$ bond.

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