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NEET CHEMISTRYMedium

Match the bond line structures of hydrocarbons given in List-I with the corresponding boiling points given in List-II.

List-II (Boiling point in K): (i) 300.9 (ii) 282.5 (iii) 309.1 (iv) 341.9

Choose the correct answer from the options given below:

A

(a)-(i), (b)-(iv), (c)-(iii), (d)-(ii)

B

(a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)

C

(a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)

D

(a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)

Step-by-Step Solution

The boiling point of alkanes depends on their molecular mass and structural branching. The boiling point increases with an increase in molecular mass due to stronger van der Waals forces . However, for isomeric alkanes, the boiling point decreases with an increase in branching because the molecule becomes more spherical, reducing the surface area of contact and the magnitude of intermolecular forces .

Based on standard NCERT data :

  1. Hexane (C6H14\text{C}_6\text{H}_{14}): 341.9 K341.9\text{ K}
  2. Pentane (C5H12\text{C}_5\text{H}_{12}, unbranched): 309.1 K309.1\text{ K}
  3. 2-Methylbutane (branched isopentane): 300.9 K300.9\text{ K}
  4. 2,2-Dimethylpropane (highly branched neopentane): 282.5 K282.5\text{ K}

Note: The specific structures for List-I (a, b, c, d) were missing from the input data. Option 2 is marked as a placeholder based on a typical alignment for this PYQ.

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