Back to Directory
NEET CHEMISTRYMedium

The pKb\text{p}K_b of dimethylamine and pKa\text{p}K_a of acetic acid are 3.273.27 and 4.774.77 respectively at T (K)T\text{ (K)}. The correct option for the pH of dimethylammonium acetate solution is:

A

7.75

B

6.25

C

8.5

D

5.5

Step-by-Step Solution

Dimethylammonium acetate is a salt formed from a weak acid (acetic acid) and a weak base (dimethylamine). For a salt of a weak acid and a weak base, the pH of its aqueous solution is calculated using the formula: pH=7+12(pKapKb)\text{pH} = 7 + \frac{1}{2}(\text{p}K_a - \text{p}K_b)

Given: pKa=4.77\text{p}K_a = 4.77 pKb=3.27\text{p}K_b = 3.27

Substituting the given values into the formula: pH=7+12(4.773.27)\text{pH} = 7 + \frac{1}{2}(4.77 - 3.27) pH=7+12(1.50)\text{pH} = 7 + \frac{1}{2}(1.50) pH=7+0.75=7.75\text{pH} = 7 + 0.75 = 7.75

Therefore, the pH of the dimethylammonium acetate solution is 7.757.75 .

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started