Which of the following equations correctly represents the standard heat of formation (\Delta fH°) of methane [IIT JEE (Screening) 1992]?
C(diamond) + 2H2(g) → CH4(g)
C(graphite) + 2H2(g) → CH4(l)
C(graphite) + 2H2(g) → CH4(g)
C(graphite) + 4H → CH4(g)
The standard molar enthalpy of formation () is defined as the enthalpy change for the formation of exactly one mole of a compound from its constituent elements in their most stable states of aggregation (reference states) . According to the sources, the reference state for carbon at 25°C and 1 bar is graphite [], and for hydrogen, it is dihydrogen gas [] . The standard state of methane at 298 K is gaseous [] . Therefore, the equation correctly represents the standard heat of formation . Other options are incorrect because they use an unstable allotrope (diamond), an incorrect physical state for the product (liquid methane), or non-molecular forms of the elements (atomic hydrogen) .
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