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NEET CHEMISTRYEasy

Which of the following equations correctly represents the standard heat of formation (\Delta fH°) of methane [IIT JEE (Screening) 1992]?

A

C(diamond) + 2H2(g) → CH4(g)

B

C(graphite) + 2H2(g) → CH4(l)

C

C(graphite) + 2H2(g) → CH4(g)

D

C(graphite) + 4H → CH4(g)

Step-by-Step Solution

The standard molar enthalpy of formation (ΔfH \Delta _fH^{\circ}) is defined as the enthalpy change for the formation of exactly one mole of a compound from its constituent elements in their most stable states of aggregation (reference states) . According to the sources, the reference state for carbon at 25°C and 1 bar is graphite [C(graphite)C(graphite)], and for hydrogen, it is dihydrogen gas [H2(g)H_2(g)] . The standard state of methane at 298 K is gaseous [CH4(g)CH_4(g)] . Therefore, the equation C(graphite)+2H2(g)CH4(g)C(graphite) + 2H_2(g) \rightarrow CH_4(g) correctly represents the standard heat of formation . Other options are incorrect because they use an unstable allotrope (diamond), an incorrect physical state for the product (liquid methane), or non-molecular forms of the elements (atomic hydrogen) .

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