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NEET CHEMISTRYHard

Which of the following is the correct sequence of reagents for converting 4-nitrotoluene to 2-bromotoluene?

A

NaNO2/HClNaNO_2/HCl; Sn/HClSn/HCl; Br2Br_2; H2O/H3PO2H_2O/H_3PO_2

B

Sn/HClSn/HCl; NaNO2/HClNaNO_2/HCl; Br2Br_2; H2O/H3PO2H_2O/H_3PO_2

C

Br2Br_2; Sn/HClSn/HCl; NaNO2/HClNaNO_2/HCl; H2O/H3PO2H_2O/H_3PO_2

D

Sn/HClSn/HCl; Br2Br_2; NaNO2/HClNaNO_2/HCl; H2O/H3PO2H_2O/H_3PO_2

Step-by-Step Solution

The conversion of 4-nitrotoluene to 2-bromotoluene involves a multi-step synthesis where the nitro group is used to direct the incoming bromine and is subsequently removed:

  1. Bromination (Br2Br_2): In 4-nitrotoluene, the CH3-CH_3 group is activating and ortho/para directing, while the NO2-NO_2 group is deactivating and meta directing. Both groups direct the incoming electrophile (Br+Br^+) to the same position: ortho to the methyl group. This forms 2-bromo-4-nitrotoluene.
  2. Reduction (Sn/HClSn/HCl): The nitro group is reduced to a primary amino group, converting 2-bromo-4-nitrotoluene to 4-amino-2-bromotoluene (or 3-bromo-4-methylaniline).
  3. Diazotisation (NaNO2/HClNaNO_2/HCl): The primary aromatic amine reacts with nitrous acid at 273-278 K to form a diazonium salt: 3-bromo-4-methylbenzenediazonium chloride.
  4. Deamination (H3PO2/H2OH_3PO_2/H_2O): The diazonium salt is treated with a mild reducing agent like hypophosphorous acid (H3PO2H_3PO_2) in the presence of water. This replaces the diazonium group (N2+Cl-N_2^+Cl^-) with a hydrogen atom (H-H), yielding the final product, 2-bromotoluene.
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