Solved: CHEMISTRY Question for NEET

NEET CHEMISTRYMedium

Consider the following sets of quantum numbers (n, l, m, s): (i) 3, 0, 0, +1/2 (ii) 2, 2, 1, +1/2 (iii) 4, 3, -2, -1/2 (iv) 1, 0, -1, -1/2 (v) 3, 2, 3, +1/2

Which of the following sets of quantum numbers is not possible?

ii, iii and iv

i, ii, iii and iv

ii, iv and v

i and iii

Step-by-Step Solution

We apply the selection rules for quantum numbers to determine validity:

Principal Quantum Number (n): Integer > 0.
Azimuthal Quantum Number (l): Integer where $0 \le l < n$ .
Magnetic Quantum Number (m): Integer where $-l \le m \le +l$ .

Evaluation of Sets:

(i) 3, 0, 0, +1/2: Valid ( $l=0 < 3$ , $m=0$ ). Corresponds to 3s.
(ii) 2, 2, 1, +1/2: Invalid. $l$ cannot equal $n$ (max $l$ for $n=2$ is 1).
(iii) 4, 3, -2, -1/2: Valid ( $l=3 < 4$ , $|-2| \le 3$ ). Corresponds to 4f.
(iv) 1, 0, -1, -1/2: Invalid. If $l=0$ , $m$ must be 0. $m=-1$ is not allowed.
(v) 3, 2, 3, +1/2: Invalid. If $l=2$ , max $m$ is +2. $m=3$ is not allowed.

Therefore, sets ii, iv, and v are not possible.

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