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NEET CHEMISTRYEasy

At 25C25^\circ\text{C}, molar conductance of 0.1 molar0.1 \text{ molar} aqueous solution of ammonium hydroxide is 9.54 ohm1cm2mol19.54 \text{ ohm}^{-1}\text{cm}^2\text{mol}^{-1} and at infinite dilution, its molar conductance is 238 ohm1cm2mol1238 \text{ ohm}^{-1}\text{cm}^2 \text{mol}^{-1}. The degree of ionization of ammonium hydroxide at the same concentration and temperature is:

A

20.80%

B

4.01%

C

40.80%

D

2.08%

Step-by-Step Solution

The degree of ionization (α\alpha) of a weak electrolyte is the ratio of its molar conductance at a given concentration (Λmc\Lambda_m^c) to its molar conductance at infinite dilution (Λm\Lambda_m^\circ). α=ΛmcΛm\alpha = \frac{\Lambda_m^c}{\Lambda_m^\circ} Given: Molar conductance at given concentration, Λmc=9.54 ohm1cm2mol1\Lambda_m^c = 9.54 \text{ ohm}^{-1}\text{cm}^2\text{mol}^{-1} Molar conductance at infinite dilution, Λm=238 ohm1cm2mol1\Lambda_m^\circ = 238 \text{ ohm}^{-1}\text{cm}^2\text{mol}^{-1} α=9.54238=0.04008\alpha = \frac{9.54}{238} = 0.04008 Percentage degree of ionization = α×100=0.04008×100=4.008%\alpha \times 100 = 0.04008 \times 100 = 4.008\%.

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