Solved: CHEMISTRY Question for NEET

NEET CHEMISTRYMedium

The behaviour of samarium ( $Z=62$ ) is very much like europium ( $Z=63$ ), since both elements:

exhibit +2 and +3 oxidation states.

have $4f^5 6s^2$ and $4f^6 6s^2$ electronic configurations, respectively.

have $4f^7 6s^2$ and $4f^8 6s^2$ electronic configurations, respectively.

have the same atomic radii.

Step-by-Step Solution

According to the properties of f-block elements, "The behaviour of samarium is very much like europium, exhibiting both +2 and +3 oxidation states" . Also, the electronic configuration of samarium ( $Z=62$ ) is $[Xe] 4f^6 6s^2$ and that of europium ( $Z=63$ ) is $[Xe] 4f^7 6s^2$ . Thus, the given electronic configuration options are incorrect. Their atomic radii also differ (Sm = 180 pm, Eu = 199 pm) .

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