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NEET CHEMISTRYEasy

The value of Planck's constant is 6.63 × 10⁻³⁴ Js. The speed of light is 3 × 10¹⁷ nm s⁻¹. Which value is closest to the wavelength in nanometers of a quantum of light with a frequency of 6 × 10¹⁵ s⁻¹?

A

25

B

50

C

75

D

10

Step-by-Step Solution

The relationship between the speed of light (cc), frequency (ν\nu), and wavelength (λ\lambda) is given by the wave equation : c=νλc = \nu \lambda

To find the wavelength (λ\lambda), we rearrange the formula: λ=cν\lambda = \frac{c}{\nu}

Given values: Speed of light (cc) = 3×1017 nm s13 \times 10^{17} \text{ nm s}^{-1} Frequency (ν\nu) = 6×1015 s16 \times 10^{15} \text{ s}^{-1}

Calculation: λ=3×10176×1015\lambda = \frac{3 \times 10^{17}}{6 \times 10^{15}} λ=0.5×102 nm\lambda = 0.5 \times 10^{2} \text{ nm} λ=50 nm\lambda = 50 \text{ nm}

(Note: Planck's constant is provided as distractor data and is not required for calculating wavelength from frequency and speed).

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