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The half-life for a zero-order reaction having 0.02 M initial concentration of reactant is 100 s. The rate constant (in mol L⁻¹ s⁻¹) for the reaction is:

A

1.0 × 10⁻⁴

B

2.0 × 10⁻⁴

C

2.0 × 10⁻³

D

1.0 × 10⁻²

Step-by-Step Solution

For a zero-order reaction, the half-life (t1/2t_{1/2}) is directly proportional to the initial concentration of the reactant ([R]0[R]_0) and inversely proportional to the rate constant (kk). The relationship is given by the equation: t1/2=[R]02kt_{1/2} = \frac{[R]_0}{2k}

To find the rate constant (kk), we rearrange the formula: k=[R]02t1/2k = \frac{[R]_0}{2t_{1/2}}

Given: Initial concentration, [R]0=0.02 M[R]_0 = 0.02 \text{ M} Half-life, t1/2=100 st_{1/2} = 100 \text{ s}

Substituting the values: k=0.02 mol L12×100 sk = \frac{0.02 \text{ mol L}^{-1}}{2 \times 100 \text{ s}} k=0.02200k = \frac{0.02}{200} k=1.0×104 mol L1 s1k = 1.0 \times 10^{-4} \text{ mol L}^{-1} \text{ s}^{-1}

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