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NEET CHEMISTRYMedium

A reaction having equal energies of activation for forward and reverse reactions has

A

ΔS=0\Delta S = 0

B

ΔG=0\Delta G = 0

C

ΔH=0\Delta H = 0

D

ΔH=ΔG=ΔS=0\Delta H = \Delta G = \Delta S = 0

Step-by-Step Solution

The enthalpy change of a reaction (ΔH\Delta H) is equal to the difference between the activation energy of the forward reaction (Ea(forward)E_{a(\text{forward})}) and the activation energy of the reverse/backward reaction (Ea(reverse)E_{a(\text{reverse})}). This relationship can be expressed as: ΔH=Ea(forward)Ea(reverse)\Delta H = E_{a(\text{forward})} - E_{a(\text{reverse})} Given that the activation energies for both the forward and reverse reactions are equal (Ea(forward)=Ea(reverse)E_{a(\text{forward})} = E_{a(\text{reverse})}), their difference becomes zero. Therefore, ΔH=0\Delta H = 0.

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