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NEET CHEMISTRYMedium

The correct IUPAC name of the following compound is:

A

2-Ethylhex-3-en-4-one

B

4-Methylhex-3-en-2-one

C

4-Ethylpent-3-en-2-one

D

3-Methylhex-3-en-4-one

Step-by-Step Solution

Based on IUPAC nomenclature rules, the principal functional group must be given the lowest possible number. Here, the ketone (>C=O>C=O) group has higher priority than the carbon-carbon double bond (C=C-C=C-) [Source 153]. The longest continuous carbon chain containing both the ketone group and the double bond is selected. If the structure is CH3COCH=C(CH3)CH2CH3CH_3-CO-CH=C(CH_3)-CH_2-CH_3 (often drawn misleadingly as a 5-carbon chain with an ethyl substituent), the longest chain actually contains 6 carbons (hex). Numbering from the end closer to the carbonyl group gives the ketone at position 2, the alkene at position 3, and a methyl group substituent at position 4. Hence, the correct IUPAC name is 4-Methylhex-3-en-2-one.

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