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NEET CHEMISTRYEasy

The measurement of the electron position is associated with an uncertainty in momentum which is equal to 1×1018 g cm s11 \times 10^{-18} \text{ g cm s}^{-1}. The uncertainty in velocity of the electron will be: (mass of an electron is 9×1028 g9 \times 10^{-28} \text{ g})

A

1 × 10⁹ cm s⁻¹

B

1 × 10⁶ cm s⁻¹

C

1 × 10⁵ cm s⁻¹

D

1 × 10¹¹ cm s⁻¹

Step-by-Step Solution

The uncertainty in momentum (Δp\Delta p) is related to the uncertainty in velocity (Δv\Delta v) and mass (mm) by the definition of momentum: Δp=mΔv\Delta p = m \cdot \Delta v.

  1. Identify Given Values: Uncertainty in momentum (Δp\Delta p) = 1×1018 g cm s11 \times 10^{-18} \text{ g cm s}^{-1} Mass of electron (mm) = 9×1028 g9 \times 10^{-28} \text{ g}

  2. Calculation: Rearranging the formula to solve for Δv\Delta v: Δv=Δpm\Delta v = \frac{\Delta p}{m} Δv=1×10189×1028\Delta v = \frac{1 \times 10^{-18}}{9 \times 10^{-28}} Δv=19×1010 cm s1\Delta v = \frac{1}{9} \times 10^{10} \text{ cm s}^{-1} Δv0.111×1010 cm s1\Delta v \approx 0.111 \times 10^{10} \text{ cm s}^{-1} Δv1.11×109 cm s1\Delta v \approx 1.11 \times 10^9 \text{ cm s}^{-1}

Rounding to the nearest integer coefficient as per the options, the value is 1×109 cm s11 \times 10^9 \text{ cm s}^{-1}.

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