Solved: CHEMISTRY Question for NEET

NEET CHEMISTRYMedium

What is the correct electronic configuration of the central atom in $K_4[Fe(CN)_6]$ based on crystal field theory?

$t_{2g}^4 e_g^2$

$t_{2g}^6 e_g^0$

$e^3 t_2^3$

$e^4 t_2^2$

Step-by-Step Solution

For $K_4[Fe(CN)_6]$ , the oxidation state of Fe is +2. The ground state of $Fe^{2+}$ is $[Ar]3d^6 4s^0$ . In the presence of a strong field ligand like $CN^-$ , the electrons pair up in the $t_{2g}$ orbitals, resulting in a configuration of $t_{2g}^6 e_g^0$ .

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