Back to Directory
NEET CHEMISTRYEasy

Which of the following expression is correct for the reaction given below? 2HI(g)→H2(g)+I2(g)2HI(g) \rightarrow H_2(g) + I_2(g)

A

−Δ[HI]Δt=2Δ[H2]Δt-\frac{\Delta[HI]}{\Delta t} = 2\frac{\Delta[H_2]}{\Delta t}

B

−Δ[HI]Δt=4Δ[I2]Δt-\frac{\Delta[HI]}{\Delta t} = 4\frac{\Delta[I_2]}{\Delta t}

C

−Δ[HI]Δt=4Δ[H2]Δt-\frac{\Delta[HI]}{\Delta t} = 4\frac{\Delta[H_2]}{\Delta t}

D

−Δ[HI]Δt=Δ[H2]Δt-\frac{\Delta[HI]}{\Delta t} = \frac{\Delta[H_2]}{\Delta t}

Step-by-Step Solution

For the reaction 2HI(g)→H2(g)+I2(g)2HI(g) \rightarrow H_2(g) + I_2(g), the rate of the reaction is expressed as: Rate=−12Δ[HI]Δt=+Δ[H2]Δt=+Δ[I2]Δt\text{Rate} = -\frac{1}{2} \frac{\Delta[HI]}{\Delta t} = +\frac{\Delta[H_2]}{\Delta t} = +\frac{\Delta[I_2]}{\Delta t} From this relationship, we can equate the rate of disappearance of HIHI with the rate of appearance of H2H_2: −12Δ[HI]Δt=Δ[H2]Δt-\frac{1}{2}\frac{\Delta[HI]}{\Delta t} = \frac{\Delta[H_2]}{\Delta t} Rearranging this gives: −Δ[HI]Δt=2Δ[H2]Δt-\frac{\Delta[HI]}{\Delta t} = 2\frac{\Delta[H_2]}{\Delta t}

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started