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The orbital angular momentum of an electron in a d-orbital is equal to:

A

√6 h/2\pi

B

√2 h/2\pi

C

2√3 h/2\pi

D

0

Step-by-Step Solution

The orbital angular momentum (LL) of an electron is determined by the azimuthal quantum number (ll) using the formula: L=l(l+1)h2π=l(l+1)L = \sqrt{l(l+1)} \frac{h}{2\pi} = \sqrt{l(l+1)} \hbar

  1. Identify Quantum Number: For a d-orbital, the azimuthal quantum number is l=2l = 2.
  2. Calculate Momentum: L=2(2+1)L = \sqrt{2(2+1)} \hbar L=6L = \sqrt{6} \hbar L=6h2πL = \sqrt{6} \frac{h}{2\pi}

(Note: The input 'hhh' typically denotes the constant unit, often represented as \hbar or h/2πh/2\pi in this context).

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