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NEET CHEMISTRYEasy

Osmotic pressure is 0.0821 atm0.0821 \text{ atm} at a temperature of 300 K300 \text{ K}. Find concentration in mole/litre:

A

0.033

B

0.066

C

0.33×1020.33 \times 10^{-2}

D

3

Step-by-Step Solution

The osmotic pressure (Π\Pi) of a solution is related to its molar concentration (CC) and temperature (TT) by the equation: Π=CRT\Pi = CRT .

Given: Osmotic Pressure (Π\Pi) = 0.0821 atm0.0821 \text{ atm} Temperature (TT) = 300 K300 \text{ K}

  • Gas Constant (RR) 0.0821 L atm K1 mol1\approx 0.0821 \text{ L atm K}^{-1} \text{ mol}^{-1} (This value is standard for pressure in atm, consistent with the provided data).

Rearranging the formula to solve for concentration (CC): C=ΠRTC = \frac{\Pi}{RT}

Substituting the values: C=0.08210.0821×300C = \frac{0.0821}{0.0821 \times 300} C=1300C = \frac{1}{300} C0.00333 mol L1C \approx 0.00333 \text{ mol L}^{-1}

Converting to scientific notation to match the options: C=0.33×102 mol L1C = 0.33 \times 10^{-2} \text{ mol L}^{-1}

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