Solved: CHEMISTRY Question for NEET | Sushrut

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NEET CHEMISTRYEasy

Percentage of C, H & N in a compound is given as follows: C=40%; H=13.33%; N=46.67% The empirical formula of the compound will be:

A

CH₂N

B

C₂H₄N

C

CH₄N

D

CH₃N

Step-by-Step Solution

Determine the number of moles of each element: Assume a $100\text{ g}$ sample of the compound.

Moles of Carbon (C): $\frac{40\text{ g}}{12\text{ g/mol}} = 3.33\text{ mol}$
Moles of Hydrogen (H): $\frac{13.33\text{ g}}{1\text{ g/mol}} = 13.33\text{ mol}$
Moles of Nitrogen (N): $\frac{46.67\text{ g}}{14\text{ g/mol}} = 3.33\text{ mol}$

Determine the simplest molar ratio: Divide the moles of each element by the smallest molar value ( $3.33\text{ mol}$ ).

C: $\frac{3.33}{3.33} = 1$
H: $\frac{13.33}{3.33} \approx 4$
N: $\frac{3.33}{3.33} = 1$

Conclusion: The simplest whole number ratio of C:H:N is $1:4:1$ . Therefore, the empirical formula is $\text{CH}_4\text{N}$ .

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