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NEET CHEMISTRYMedium

Which one of the following arrangements does not give the correct picture of the trends indicated against it?

A

F₂ > Cl₂ > Br₂ > I₂ : Oxidising power

B

Cl₂ > F₂ > Br₂ > I₂ : Electron gain enthalpy

C

F₂ > Cl₂ > Br₂ > I₂ : Bond dissociation energy

D

F₂ > Cl₂ > Br₂ > I₂ : Electronegativity

Step-by-Step Solution

We evaluate the trends for Group 17 elements (Halogens):

  1. Oxidising Power: Fluorine is the strongest oxidising agent due to its high hydration enthalpy and low bond dissociation enthalpy. The trend F2>Cl2>Br2>I2F_2 > Cl_2 > Br_2 > I_2 is correct (Supported by standard electrode potentials: F2F_2 = +2.87 V, I2I_2 = +0.54 V) .
  2. Electron Gain Enthalpy: Chlorine has the most negative electron gain enthalpy. Fluorine is less negative than Chlorine due to inter-electronic repulsion in its small 2p subshell. The trend Cl2>F2>Br2>I2Cl_2 > F_2 > Br_2 > I_2 is correct.
  3. Electronegativity: Fluorine is the most electronegative element. The trend decreases down the group (F>Cl>Br>IF > Cl > Br > I). This is correct.
  4. Bond Dissociation Energy: One might expect bond energy to decrease down the group as size increases (FF>ClCl>...F-F > Cl-Cl > ...). However, due to the very small size of Fluorine, there is strong lone pair-lone pair repulsion between the non-bonding electrons, which weakens the F-F bond. Consequently, the bond dissociation energy of F2F_2 is lower than that of Cl2Cl_2 and Br2Br_2. The correct order is Cl2>Br2>F2>I2Cl_2 > Br_2 > F_2 > I_2. Therefore, the given trend F2>Cl2>Br2>I2F_2 > Cl_2 > Br_2 > I_2 is incorrect.
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