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NEET CHEMISTRYEasy

Limiting molar conductivity of NH4OH\text{NH}_4\text{OH} (i.e. Λm(NH4OH)\Lambda^\circ_m(\text{NH}_4\text{OH})) is equal to:

A

Λm(NH4Cl)+Λm(NaCl)Λm(NaOH)\Lambda^\circ_m(\text{NH}_4\text{Cl}) + \Lambda^\circ_m(\text{NaCl}) - \Lambda^\circ_m(\text{NaOH})

B

Λm(NaOH)+Λm(NaCl)Λm(NH4Cl)\Lambda^\circ_m(\text{NaOH}) + \Lambda^\circ_m(\text{NaCl}) - \Lambda^\circ_m(\text{NH}_4\text{Cl})

C

Λm(NH4OH)+Λm(NH4Cl)Λm(HCl)\Lambda^\circ_m(\text{NH}_4\text{OH}) + \Lambda^\circ_m(\text{NH}_4\text{Cl}) - \Lambda^\circ_m(\text{HCl})

D

Λm(NH4Cl)+Λm(NaOH)Λm(NaCl)\Lambda^\circ_m(\text{NH}_4\text{Cl}) + \Lambda^\circ_m(\text{NaOH}) - \Lambda^\circ_m(\text{NaCl})

Step-by-Step Solution

According to Kohlrausch's law of independent migration of ions, the limiting molar conductivity of an electrolyte can be represented as the sum of the individual contributions of the anion and cation of the electrolyte. Λm(NH4OH)=λNH4++λOH\Lambda^\circ_m(\text{NH}_4\text{OH}) = \lambda^\circ_{\text{NH}_4^+} + \lambda^\circ_{\text{OH}^-} This can be obtained from the limiting molar conductivities of strong electrolytes NH4Cl\text{NH}_4\text{Cl}, NaOH\text{NaOH}, and NaCl\text{NaCl} as follows: Λm(NH4Cl)+Λm(NaOH)Λm(NaCl)\Lambda^\circ_m(\text{NH}_4\text{Cl}) + \Lambda^\circ_m(\text{NaOH}) - \Lambda^\circ_m(\text{NaCl}) =(λNH4++λCl)+(λNa++λOH)(λNa++λCl)= (\lambda^\circ_{\text{NH}_4^+} + \lambda^\circ_{\text{Cl}^-}) + (\lambda^\circ_{\text{Na}^+} + \lambda^\circ_{\text{OH}^-}) - (\lambda^\circ_{\text{Na}^+} + \lambda^\circ_{\text{Cl}^-}) =λNH4++λOH=Λm(NH4OH)= \lambda^\circ_{\text{NH}_4^+} + \lambda^\circ_{\text{OH}^-} = \Lambda^\circ_m(\text{NH}_4\text{OH})

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