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Coordination compound that would exhibit optical isomerism is:

A

Diamminedichloroplatinum(II)

B

Trans-dicyanobis(ethylenediamine)chromium(III) chloride

C

Tris-(ethylenediamine)cobalt(III) chloride

D

Pentaamminenitrocobalt(III) iodide

Step-by-Step Solution

Optical isomerism is exhibited by coordination compounds that lack any plane or centre of symmetry (i.e., chiral complexes) .

  1. Diamminedichloroplatinum(II), [Pt(NH3)2Cl2][Pt(NH_3)_2Cl_2], is a square planar complex and possesses a plane of symmetry, making it optically inactive.
  2. Trans-dicyanobis(ethylenediamine)chromium(III) chloride, trans[Cr(en)2(CN)2]Cltrans-[Cr(en)_2(CN)_2]Cl, has a plane of symmetry cutting through the metal and the symmetrical ligands, making it optically inactive. (Note: Its cis-isomer is optically active) .
  3. Tris-(ethylenediamine)cobalt(III) chloride, [Co(en)3]Cl3[Co(en)_3]Cl_3, is an octahedral complex of the type [M(AA)3]n+[M(AA)_3]^{n+} containing didentate ligands. It lacks a plane of symmetry and therefore exhibits optical isomerism, existing as non-superimposable dextro (dd) and laevo (ll) enantiomers .
  4. Pentaamminenitrocobalt(III) iodide, [Co(NH3)5(NO2)]I2[Co(NH_3)_5(NO_2)]I_2, is of the type [Ma5b]n+[Ma_5b]^{n+} and has a plane of symmetry, making it optically inactive.
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