Back to Directory
NEET CHEMISTRYEasy

The number of atoms in 0.1 mole0.1\text{ mole} of a triatomic gas is: (NA=6.02×1023 mol−1N_A = 6.02 \times 10^{23}\text{ mol}^{-1})

A

6.02×10226.02 \times 10^{22}

B

1.806×10231.806 \times 10^{23}

C

3.600×10233.600 \times 10^{23}

D

1.800×10221.800 \times 10^{22}

Step-by-Step Solution

Number of moles of the gas = 0.1 mol0.1\text{ mol}. Number of molecules in 0.1 mol0.1\text{ mol} of the gas = 0.1×NA=0.1×6.02×1023=6.02×1022 molecules0.1 \times N_A = 0.1 \times 6.02 \times 10^{23} = 6.02 \times 10^{22}\text{ molecules}. Since it is a triatomic gas, each molecule contains 3 atoms3\text{ atoms}. Therefore, the total number of atoms = 3×6.02×1022=18.06×1022=1.806×1023 atoms3 \times 6.02 \times 10^{22} = 18.06 \times 10^{22} = 1.806 \times 10^{23}\text{ atoms}.

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started
Solved: CHEMISTRY Question for NEET | Sushrut