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NEET CHEMISTRYMedium

Which amongst the following will be most readily dehydrated under acidic conditions?

A

Option 1 (Structure Missing)

B

Option 2 (Structure Missing)

C

Option 3 (Structure Missing)

D

Option 4

Step-by-Step Solution

The dehydration of alcohols under acidic conditions proceeds via an E1 mechanism involving the formation of a carbocation intermediate. The rate-determining step is the formation of this carbocation. Therefore, the alcohol that forms the most stable carbocation will be the most readily dehydrated.

Reactivity Order:

  1. Carbocation Stability: The stability order is Tertiary (33^{\circ}) > Secondary (22^{\circ}) > Primary (11^{\circ}).
  2. Resonance: Alcohols that form allylic or benzylic carbocations are even more reactive due to resonance stabilization.
  3. Electron Withdrawing Groups: Presence of electron-withdrawing groups (like NO2-NO_2 or C=O-C=O) adjacent to the carbocation center destabilizes it, reducing reactivity.

Option 4 likely contains a structure that yields a stable tertiary carbocation or one stabilized by resonance, making it the most reactive.

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