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During the kinetic study of the reaction, 2A + B → C + D, following results were obtained:

| Run | [A] / mol L⁻¹ | [B] / mol L⁻¹ | Initial rate of formation of D / mol L⁻¹ min⁻¹ | | :--- | :--- | :--- | :--- | | I | 0.1 | 0.1 | 6.0 × 10⁻³ | | II | 0.3 | 0.2 | 7.2 × 10⁻² | | III | 0.3 | 0.4 | 2.88 × 10⁻¹ | | IV | 0.4 | 0.1 | 2.40 × 10⁻² |

Based on the above data which one of the following is correct?

A

rate = k[A]²[B]

B

rate = k[A][B]

C

rate = k[A]²[B]²

D

rate = k[A][B]²

Step-by-Step Solution

To determine the rate law, we compare the initial rates from different experiments where the concentration of one reactant changes while the other remains constant .

  1. Determine order with respect to A: Compare Run I and Run IV. [B] is constant (0.1 M). [A] increases by a factor of 4 (0.1 → 0.4). Rate increases by a factor of 4 (2.40×102/6.0×103=42.40 \times 10^{-2} / 6.0 \times 10^{-3} = 4). Since rate [A]x\propto [A]^x, 4=4xx=14 = 4^x \Rightarrow x = 1. The reaction is first order w.r.t. A.

  2. Determine order with respect to B: Compare Run II and Run III. [A] is constant (0.3 M). [B] increases by a factor of 2 (0.2 → 0.4). Rate increases by a factor of 4 (2.88×101/7.2×102=42.88 \times 10^{-1} / 7.2 \times 10^{-2} = 4). Since rate [B]y\propto [B]^y, 4=2yy=24 = 2^y \Rightarrow y = 2. The reaction is second order w.r.t. B.

Conclusion: The rate law is Rate = k[A][B]².

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