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NEET CHEMISTRYMedium

The weight of silver (atomic weight = 108108) displaced by a quantity of electricity which displaces 5600 mL5600 \text{ mL} of O2\text{O}_2 at STP will be :

A

5.4 g5.4 \text{ g}

B

10.8 g10.8 \text{ g}

C

54.0 g54.0 \text{ g}

D

108.0 g108.0 \text{ g}

Step-by-Step Solution

At STP, the molar volume of an ideal gas is 22400 mL/mol22400 \text{ mL/mol}. Moles of O2\text{O}_2 displaced = 5600 mL22400 mL/mol=0.25 mol\frac{5600 \text{ mL}}{22400 \text{ mL/mol}} = 0.25 \text{ mol}.

The half-reaction for the liberation of O2\text{O}_2 is: 2H2OO2+4H++4e2\text{H}_2\text{O} \rightarrow \text{O}_2 + 4\text{H}^+ + 4e^- This shows that 1 mole1 \text{ mole} of O2\text{O}_2 gas is produced by the passage of 4 moles4 \text{ moles} of electrons (4 Faradays4 \text{ Faradays}). Therefore, the charge (QQ) required to displace 0.25 moles0.25 \text{ moles} of O2=0.25×4=1 Faraday\text{O}_2 = 0.25 \times 4 = 1 \text{ Faraday}.

The half-reaction for the deposition of silver is: Ag++eAg\text{Ag}^+ + e^- \rightarrow \text{Ag} This shows that 1 Faraday1 \text{ Faraday} of electricity deposits 1 mole1 \text{ mole} of Ag\text{Ag}. Mass of 1 mole1 \text{ mole} of Ag=108 g\text{Ag} = 108 \text{ g}.

Thus, the weight of silver displaced by 1 Faraday1 \text{ Faraday} of electricity is 108.0 g108.0 \text{ g}.

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