Solved: CHEMISTRY Question for NEET

NEET CHEMISTRYMedium

An alkene reacts in accordance with Markownikoff's rule to give a product of 1-chloro-1-methylcyclohexane with HCl. The possible alkene is:

(Option 1 Structure Missing)

(Option 2 Structure Missing)

Both 1 and 2

(Option 4 Structure Missing)

Reaction: The reaction involves the addition of $HCl$ to an alkene. This is an electrophilic addition reaction governed by Markovnikov's Rule .
Product Analysis: The product is 1-chloro-1-methylcyclohexane. This structure has a chlorine atom and a methyl group both attached to the same carbon (C1) of the cyclohexane ring. This is a tertiary alkyl halide.
Retrosynthetic Analysis (Identifying Reactants): To form this product via Markovnikov addition:

The proton ( $H^+$ ) from HCl must add to a carbon of the double bond to form the stable tertiary carbocation at C1 (where the methyl group is attached).
The chloride ion ( $Cl^-$ ) then attacks this tertiary carbocation.

Possible Alkenes: Two alkenes can generate this specific tertiary carbocation:

1-Methylcyclohexene: The double bond is between C1 (with methyl) and C2. $H^+$ adds to C2 (less substituted), generating the $3^{\circ}$ carbocation at C1.
Methylenecyclohexane: The double bond is exocyclic (between the ring carbon and an external $CH_2$ ). $H^+$ adds to the external $CH_2$ , generating the $3^{\circ}$ carbocation at the ring carbon.

Conclusion: Both 1-Methylcyclohexene and Methylenecyclohexane yield the same major product, 1-chloro-1-methylcyclohexane, upon reaction with HCl. Therefore, the answer is likely "Both 1 and 2" assuming these are the structures for options 1 and 2.

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