The energies E₁ and E₂ of two radiations are 25 eV and 50 eV respectively. The relation between their wavelengths i.e., \lambda ₁ and \lambda ₂ will be:
\lambda ₁ = 2\lambda ₂
\lambda ₁ = 4\lambda ₂
\lambda ₁ = ½\lambda ₂
\lambda ₁ = \lambda ₂
The energy () of a photon or radiation is inversely proportional to its wavelength () according to the Planck-Einstein relation: where is Planck's constant and is the speed of light.
Since is constant, we can write the ratio:
Given:
Calculation:
Thus, the wavelength of the first radiation is twice that of the second.
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