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NEET CHEMISTRYMedium

The maximum number of molecules is present in:

A

5L of N₂ gas at STP

B

0.5 g of H₂ gas

C

10g of O₂ gas

D

15 L of H₂ gas at STP

Step-by-Step Solution

  1. Identify the Principle: The number of molecules is directly proportional to the number of moles (nn).
  • For gases at STP (Standard Temperature and Pressure), n=Volume (L)22.4n = \frac{\text{Volume (L)}}{22.4}.
  • For mass, n=Mass (g)Molar Mass (g/mol)n = \frac{\text{Mass (g)}}{\text{Molar Mass (g/mol)}}.
  1. Calculate Moles for each option:
  • Option 1: 5 L5\text{ L} of N2N_2 at STP. n=522.40.223 moln = \frac{5}{22.4} \approx 0.223 \text{ mol}
  • Option 2: 0.5 g0.5\text{ g} of H2H_2. Molar mass of H2=2 g/molH_2 = 2\text{ g/mol}. n=0.52=0.25 moln = \frac{0.5}{2} = 0.25 \text{ mol}
  • Option 3: 10 g10\text{ g} of O2O_2. Molar mass of O2=32 g/molO_2 = 32\text{ g/mol}. n=1032=0.3125 moln = \frac{10}{32} = 0.3125 \text{ mol}
  • Option 4: 15 L15\text{ L} of H2H_2 at STP. n=1522.40.67 moln = \frac{15}{22.4} \approx 0.67 \text{ mol}
  1. Conclusion: Option 4 has the highest number of moles (0.670.67), therefore it contains the maximum number of molecules.
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