The alkane that gives only one monochloro product on chlorination with Cl2 in presence of diffused sunlight is:
A
2,2-Dimethylbutane
B
Neopentane
C
n-Pentane
D
Isopentane
Step-by-Step Solution
Principle of Monochlorination: Free radical chlorination replaces a hydrogen atom with a chlorine atom. The number of isomeric monochloro products formed depends on the number of chemically non-equivalent sets of hydrogen atoms present in the alkane molecule [NCERT 11th, Ch 13, Sec 13.5.2; NCERT 12th, Ch 10, Ex 10.3]. If an alkane has only one type of hydrogen, it yields a single monochloro product.
Analyze Option B (Neopentane / 2,2-Dimethylpropane):
Structure: A central quaternary carbon bonded to four methyl groups (C(CH3)4).
Symmetry: All 12 hydrogen atoms belong to identical methyl groups attached to the same central atom. They are chemically equivalent.
Product: Replacing any one of the 12 hydrogens results in the same compound: 1-chloro-2,2-dimethylpropane.
Analyze Other Options:
n-Pentane (CH3CH2CH2CH2CH3): Has 3 sets of equivalent hydrogens (C1/C5, C2/C4, and C3), yielding 3 isomers.
Isopentane (2-Methylbutane): Has 4 different sets of hydrogens, yielding 4 isomers.
2,2-Dimethylbutane: Has 3 different sets of hydrogens, yielding 3 isomers.
Conclusion: Neopentane is the only alkane listed that yields a single monochloro product.
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