Solved: CHEMISTRY Question for NEET

NEET CHEMISTRYEasy

A solution contains a non-volatile solute of molecular mass $M_2$ . Which of the following expressions gives the molecular mass of solute in terms of osmotic pressure, where $m_2$ is the mass of solute, $V$ is the volume of solution, and $\pi$ is osmotic pressure?

$M_2 = \frac{m_2 \pi}{V R T}$

$M_2 = \frac{m_2 R T}{\pi V}$

$M_2 = \frac{m_2 V \pi}{R T}$

$M_2 = \frac{m_2 V}{R T \pi}$

Step-by-Step Solution

Osmotic pressure ( $\pi$ or $\Pi$ ) is related to the molar concentration ( $C$ ) of the solution by the equation $\pi = CRT$ .

Express Concentration ( $C$ ): $C = \frac{n_2}{V}$ , where $n_2$ is the number of moles of solute and $V$ is the volume of the solution in litres.
Express Moles ( $n_2$ ): $n_2 = \frac{m_2}{M_2}$ , where $m_2$ is the mass of the solute and $M_2$ is its molar mass.
Substitute into the Osmotic Pressure Equation: $\pi = \frac{m_2}{M_2 V} R T$
Rearrange to solve for $M_2$ : $M_2 = \frac{m_2 R T}{\pi V}$

This relationship allows for the determination of molar masses of solutes .

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