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A compound X contains 32% of A, 20% of B and remaining percentage of C. Then, the empirical formula of X is: (Given atomic mass of A = 64; B = 40; C = 32 u)

A

ABC₃

B

AB₂C₂

C

ABC₄

D

A₂BC₂

Step-by-Step Solution

  1. Calculate Percentage of C: %C=100−(%A+%B)=100−(32+20)=48%\%C = 100 - (\%A + \%B) = 100 - (32 + 20) = 48\%
  2. Calculate Relative Number of Moles: Divide the percentage composition by the respective atomic masses.
  • For A: 3264=0.5\frac{32}{64} = 0.5
  • For B: 2040=0.5\frac{20}{40} = 0.5
  • For C: 4832=1.5\frac{48}{32} = 1.5
  1. Determine Simplest Whole Number Ratio: Divide each value by the smallest number of moles (0.5).
  • A: 0.50.5=1\frac{0.5}{0.5} = 1
  • B: 0.50.5=1\frac{0.5}{0.5} = 1
  • C: 1.50.5=3\frac{1.5}{0.5} = 3
  1. Conclusion: The empirical formula is A1B1C3A_1B_1C_3 or ABC3ABC_3.
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