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NEET CHEMISTRYMedium

Acetone is treated with excess ethanol in the presence of hydrochloric acid. The product obtained will be:

A

Option 1 (Image Missing)

B

Option 2 (Image Missing)

C

Option 3: 4.

D

Option 4 (Image Missing)

Step-by-Step Solution

When ketones (like acetone) are treated with alcohols (like ethanol) in the presence of dry hydrogen chloride gas (acid catalyst), they undergo nucleophilic addition.

  1. Hemiketal Formation: The first molecule of ethanol adds to the carbonyl group to form an unstable hemiketal.
  2. Ketal Formation: Since ethanol is present in excess, a second molecule of ethanol reacts with the hemiketal, eliminating a water molecule to form a stable ketal.

Reaction: (CH3)2C=O+2C2H5OH→HCl(dry)(CH3)2C(OC2H5)2+H2O(CH_3)_2C=O + 2C_2H_5OH \xrightarrow{HCl(dry)} (CH_3)_2C(OC_2H_5)_2 + H_2O

The product is 2,2-Diethoxypropane, commonly known as acetone diethyl ketal.

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