Solved: CHEMISTRY Question for NEET

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NEET CHEMISTRYEasy

Which of the following is not permissible arrangement of electrons in an atom?

n = 4, l = 0, m = 0, s = –1/2

n = 5, l = 3, m = 0, s = +1/2

n = 3, l = 2, m = –3, s = –1/2

n = 3, l = 2, m = –2, s = –1/2

Step-by-Step Solution

The permissible values for quantum numbers are governed by specific rules:

Principal Quantum Number ( $n$ ): Must be a positive integer ( $1, 2, 3, ...$ ).
Azimuthal Quantum Number ( $l$ ): Must be an integer from $0$ to $(n-1)$ .
Magnetic Quantum Number ( $m_l$ ): Must be an integer ranging from $-l$ to $+l$ (including zero).
Spin Quantum Number ( $s$ ): Must be $+1/2$ or $-1/2$ .

Analysis of Option C: Given $n = 3$ and $l = 2$ . The permissible values for $m$ are $-2, -1, 0, +1, +2$ . The value $m = -3$ is not permissible because its magnitude exceeds $l$ .

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