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Match List-I with List-II:

List-I (Test) (a) Carbylamine test (b) Baeyer's test (c) Iodoform test (d) Phthalein dye test

List-II (Compound) (i) Phenol (ii) Acetone (iii) Ethylene (iv) Aniline

Choose the correct answer from the options given below:

A

(a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)

B

(a)-(iv), (b)-(ii), (c)-(iii), (d)-(i)

C

(a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)

D

(a)-(ii), (b)-(iii), (c)-(i), (d)-(iv)

Step-by-Step Solution

Let's match the chemical tests with their respective target compounds:

  1. Carbylamine test: This is a characteristic test for primary amines (both aliphatic and aromatic). Aniline is a primary aromatic amine and gives a positive carbylamine test by forming a foul-smelling isocyanide. [(a) \rightarrow (iv)]
  2. Baeyer's test: This test is used to detect the presence of unsaturation (carbon-carbon double or triple bonds). Ethylene contains a double bond and will decolourise the cold, dilute alkaline KMnO4KMnO_4 solution (Baeyer's reagent). [(b) \rightarrow (iii)]
  3. Iodoform test: This test is given by compounds having a methyl ketone group (COCH3-COCH_3) or a methyl carbinol group. Acetone (CH3COCH3CH_3COCH_3) contains a methyl ketone group and forms a yellow precipitate of iodoform (CHI3CHI_3) upon reaction with iodine and alkali. [(c) \rightarrow (ii)]
  4. Phthalein dye test: This test is specific for phenols. Phenol reacts with phthalic anhydride in the presence of concentrated H2SO4H_2SO_4 to form phenolphthalein, which turns pink in an alkaline medium. [(d) \rightarrow (i)]

Therefore, the correct matching is (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i).

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