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NEET CHEMISTRYEasy

The value of Planck's constant is 6.63×1034 J s6.63 \times 10^{-34} \text{ J s}. The velocity of light is 3.0×108 m s13.0 \times 10^8 \text{ m s}^{-1}. The closest value to the wavelength in nanometers of a quantum of light with a frequency of 8×1015 s18 \times 10^{15} \text{ s}^{-1} is:

A

2 \times 10^{-25}

B

5 \times 10^{-18}

C

4 \times 10^1

D

3 \times 10^7

Step-by-Step Solution

The relationship between the speed of light (cc), frequency (ν\nu), and wavelength (λ\lambda) is given by the equation: c=νλc = \nu \lambda Rearranging to solve for wavelength (λ\lambda): λ=cν\lambda = \frac{c}{\nu} Given: c=3.0×108 m s1c = 3.0 \times 10^8 \text{ m s}^{-1} ν=8×1015 s1\nu = 8 \times 10^{15} \text{ s}^{-1}

Calculation: λ=3.0×1088×1015 m\lambda = \frac{3.0 \times 10^8}{8 \times 10^{15}} \text{ m} λ=0.375×107 m\lambda = 0.375 \times 10^{-7} \text{ m} λ=3.75×108 m\lambda = 3.75 \times 10^{-8} \text{ m}

To convert the wavelength into nanometers (1 nm=109 m1 \text{ nm} = 10^{-9} \text{ m}): λ=3.75×108 m×109 nm1 m\lambda = 3.75 \times 10^{-8} \text{ m} \times \frac{10^9 \text{ nm}}{1 \text{ m}} λ=3.75×101 nm\lambda = 3.75 \times 10^1 \text{ nm} λ=37.5 nm\lambda = 37.5 \text{ nm}

The closest value among the options is 4×1014 \times 10^1 (which is 40).

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