Solved: CHEMISTRY Question for NEET | Sushrut

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NEET CHEMISTRYEasy

Which of the following pairs of species have the same bond order?

A

O $_2^-$ , NO $^+$

B

CN $^-$ , CO

C

N $_2$ , O $_2^-$

D

CO, NO

Step-by-Step Solution

Isoelectronic Principle: Species having the same number of total electrons are called isoelectronic. Isoelectronic species usually have the same bond order .
Analyze Option B ( $CN^-$ and $CO$ ):

$CN^-$ : Number of electrons = 6 (C) + 7 (N) + 1 (negative charge) = 14 electrons.
$CO$ : Number of electrons = 6 (C) + 8 (O) = 14 electrons.
Since both have 14 electrons (isoelectronic with $N_2$ ), they both have a bond order of 3.

Analyze other options:

Option A: $O_2^-$ (17 $e^-$ ) has B.O. = 1.5, while $NO^+$ (14 $e^-$ ) has B.O. = 3.
Option C: $N_2$ (14 $e^-$ ) has B.O. = 3, while $O_2^-$ (17 $e^-$ ) has B.O. = 1.5.
Option D: $CO$ (14 $e^-$ ) has B.O. = 3, while $NO$ (15 $e^-$ ) has B.O. = 2.5.

Conclusion: The pair $CN^-$ and $CO$ have the same bond order.

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