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NEET CHEMISTRYEasy

pAp_A and pBp_B are the vapour pressures of pure liquid components A and B, respectively, of an ideal binary solution. If xAx_A represents the mole fraction of component A, the total pressure of the solution will be:

A

pA+xA(pBpA)p_A + x_A(p_B - p_A)

B

pA+xA(pApB)p_A + x_A(p_A - p_B)

C

pB+xA(pBpA)p_B + x_A(p_B - p_A)

D

pB+xA(pApB)p_B + x_A(p_A - p_B)

Step-by-Step Solution

For an ideal binary solution containing components A and B, the partial vapour pressures according to Raoult's law are: PA=xApAP_A = x_A p_A PB=xBpBP_B = x_B p_B According to Dalton's law of partial pressures, the total pressure of the solution (PtotalP_{\text{total}}) is the sum of the partial pressures: Ptotal=PA+PB=xApA+xBpBP_{\text{total}} = P_A + P_B = x_A p_A + x_B p_B We know that the sum of mole fractions of all components in a solution is unity, i.e., xA+xB=1x_A + x_B = 1, which gives xB=1xAx_B = 1 - x_A. Substituting this into the total pressure equation: Ptotal=xApA+(1xA)pBP_{\text{total}} = x_A p_A + (1 - x_A) p_B Ptotal=xApA+pBxApBP_{\text{total}} = x_A p_A + p_B - x_A p_B Ptotal=pB+xA(pApB)P_{\text{total}} = p_B + x_A(p_A - p_B)

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