Back to Directory
NEET CHEMISTRYMedium

The correct 'spin only' magnetic moments of [CoF6]3[CoF_6]^{3-} and [Co(C2O4)3]3[Co(C_2O_4)_3]^{3-} respectively, are:

A

0 BM and 4.9 BM

B

0 BM and 0 BM

C

4.9 BM and 0 BM

D

4.9 BM and 4.9 BM

Step-by-Step Solution

In [CoF6]3[CoF_6]^{3-}, the central metal ion Co is in the +3 oxidation state, which has a 3d63d^6 electronic configuration. Since FF^- is a weak field ligand, the crystal field splitting energy is less than the pairing energy (Δo<P\Delta_o < P). Thus, it forms a high-spin complex with the configuration t2g4eg2t_{2g}^4 e_g^2. It has 4 unpaired electrons (n=4n=4). The spin-only magnetic moment is μ=4(4+2)=244.9\mu = \sqrt{4(4+2)} = \sqrt{24} \approx 4.9 BM.

In [Co(C2O4)3]3[Co(C_2O_4)_3]^{3-}, Co is also in the +3 oxidation state (3d63d^6). However, the oxalate ligand (C2O42C_2O_4^{2-}), being a chelating ligand, acts as a strong field ligand when complexed with Co3+Co^{3+}. This causes the electrons to pair up (Δo>P\Delta_o > P), resulting in a low-spin complex with the configuration t2g6eg0t_{2g}^6 e_g^0. It has 0 unpaired electrons (n=0n=0), meaning it is diamagnetic with a magnetic moment of 0 BM.

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started
Solved: CHEMISTRY Question for NEET | Sushrut