Solved: CHEMISTRY Question for NEET | Sushrut

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NEET CHEMISTRYMedium

An isostructural compound with $XeF_2$ among the following is:

A

ICl₂⁻

B

SbCl₃

C

BaCl₂

D

TeF₂

Step-by-Step Solution

Analyze $XeF_2$ :

Central atom Xenon (Xe) has 8 valence electrons.
It forms 2 sigma bonds with Fluorine.
Remaining electrons = $8 - 2 = 6$ (3 lone pairs).
Structure: 2 Bond Pairs + 3 Lone Pairs $\rightarrow$ Linear geometry (Lone pairs occupy equatorial positions in trigonal bipyramidal electron geometry).

Analyze Option A ( $ICl_2^-$ ):

Central atom Iodine (I) has 7 valence electrons.
Negative charge adds 1 electron $\rightarrow$ Total 8 valence electrons on the central shell context.
It forms 2 sigma bonds with Chlorine.
Remaining electrons = $8 - 2 = 6$ (3 lone pairs).
Structure: 2 Bond Pairs + 3 Lone Pairs $\rightarrow$ Linear geometry.
Since both have the same structure (Linear) and hybridization ( $sp^3d$ ), they are isostructural.

Analyze other options:

$SbCl_3$ : 3 Bond Pairs + 1 Lone Pair $\rightarrow$ Trigonal Pyramidal.
$BaCl_2$ : Ionic/Linear (but typically considered distinct from covalent VSEPR analogs in this context).
$TeF_2$ : 2 Bond Pairs + 2 Lone Pairs $\rightarrow$ Bent/Angular.

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