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NEET CHEMISTRYMedium

The sum of coordination number and oxidation number of the metal M in the complex [M(en)2(C2O4)]Cl[M(en)_2(C_2O_4)]Cl (where, en is ethylenediamine) is:

A

9

B

6

C

7

D

8

Step-by-Step Solution

In the complex [M(en)2(C2O4)]Cl[M(en)_2(C_2O_4)]Cl:

  1. Coordination Number (CN): The ligands are ethylenediamine (enen), which is a neutral didentate ligand, and oxalate (C2O42C_2O_4^{2-}), which is an anionic didentate ligand. Total number of donor atoms bound to the metal M=(2×2)+(1×2)=6M = (2 \times 2) + (1 \times 2) = 6. Therefore, the coordination number is 6.
  2. Oxidation Number (ON): Let the oxidation state of metal M be xx. The overall charge on the complex cation [M(en)2(C2O4)]+[M(en)_2(C_2O_4)]^+ is +1+1 (to balance the ClCl^- counter ion). So, x+2(0)+1(2)=+1x2=+1x=+3x + 2(0) + 1(-2) = +1 \Rightarrow x - 2 = +1 \Rightarrow x = +3. The oxidation number is 3.

The sum of the coordination number and oxidation number is 6+3=96 + 3 = 9.

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