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Urea reacts with water to form A which will decompose to form B. B when passed through Cu2+(aq)Cu^{2+}(aq), deep blue colour solution C is formed. What is the formula of C from the following?

A

[Cu(NH3)4]2+[Cu(NH_3)_4]^{2+}

B

Cu(OH)2Cu(OH)_2

C

CuCO3⋅Cu(OH)2CuCO_3 \cdot Cu(OH)_2

D

CuSO4CuSO_4

Step-by-Step Solution

  1. Hydrolysis of Urea: Urea (NH2CONH2NH_2CONH_2) reacts with water to form ammonium carbonate (A). NH2CONH2+2H2O→(NH4)2CO3NH_2CONH_2 + 2H_2O \rightarrow (NH_4)_2CO_3
  2. Decomposition: Ammonium carbonate (A) decomposes to give ammonia (B), water, and carbon dioxide. (NH4)2CO3⇌2NH3+H2O+CO2(NH_4)_2CO_3 \rightleftharpoons 2NH_3 + H_2O + CO_2 Thus, compound B is Ammonia (NH3NH_3).
  3. Reaction with Cu2+Cu^{2+}: When ammonia (B) is passed through a solution containing copper(II) ions (Cu2+Cu^{2+}), it acts as a ligand and forms a coordination complex. The specific complex formed is the tetraamminecopper(II) ion, which is characterized by a deep blue colour. Cu2+(aq)+4NH3(aq)⇌[Cu(NH3)4]2+(aq) (Deep Blue)Cu^{2+}(aq) + 4NH_3(aq) \rightleftharpoons [Cu(NH_3)_4]^{2+}(aq) \text{ (Deep Blue)} This reaction is a standard qualitative test for copper ions and the formation of this deep blue complex is explicitly mentioned in the study of coordination compounds .
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