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NEET CHEMISTRYMedium

Which of the statements is not true?

A

On passing H2S\text{H}_2\text{S} through acidified K2Cr2O7\text{K}_2\text{Cr}_2\text{O}_7 solution, a milky colour is observed

B

Na2Cr2O7\text{Na}_2\text{Cr}_2\text{O}_7 is preferred over K2Cr2O7\text{K}_2\text{Cr}_2\text{O}_7 in volumetric analysis

C

K2Cr2O7\text{K}_2\text{Cr}_2\text{O}_7 solution in acidic medium is orange

D

K2Cr2O7\text{K}_2\text{Cr}_2\text{O}_7 solution becomes yellow on increasing the pH beyond 7

Step-by-Step Solution

Potassium dichromate (K2Cr2O7\text{K}_2\text{Cr}_2\text{O}_7) is used as a primary standard in volumetric analysis because it is not deliquescent and its crystals can be weighed accurately. On the other hand, sodium dichromate (Na2Cr2O7\text{Na}_2\text{Cr}_2\text{O}_7) is deliquescent (absorbs moisture from the air) and cannot be used as a primary standard. Therefore, the statement 'Na2Cr2O7\text{Na}_2\text{Cr}_2\text{O}_7 is preferred over K2Cr2O7\text{K}_2\text{Cr}_2\text{O}_7 in volumetric analysis' is incorrect.

The other statements are true:

  • Acidified K2Cr2O7\text{K}_2\text{Cr}_2\text{O}_7 oxidises H2S\text{H}_2\text{S} to elemental sulphur, which appears milky.
  • In an acidic medium, the dichromate ion (Cr2O72\text{Cr}_2\text{O}_7^{2-}) is stable and imparts an orange colour to the solution.
  • On increasing the pH beyond 7 (making the medium basic), the orange dichromate ion converts into the yellow chromate ion (CrO42\text{CrO}_4^{2-}).
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