Back to Directory
NEET CHEMISTRYEasy

If the energy value is E=3.03×10−19 JoulesE = 3.03 \times 10^{-19} \text{ Joules}, (h=6.6×10−34 J sh = 6.6 \times 10^{-34} \text{ J s}, c=3×108 m/sc = 3 \times 10^8 \text{ m/s}), then the value of the corresponding wavelength is:

A

65.3 nm

B

6.53 nm

C

3.4 nm

D

653 nm

Step-by-Step Solution

The energy (EE) of a photon is related to its wavelength (λ\lambda) by the Planck's equation: E=hcλE = \frac{hc}{\lambda}

Rearranging the formula to solve for wavelength: λ=hcE\lambda = \frac{hc}{E}

Given: Planck's constant, h=6.6×10−34 J sh = 6.6 \times 10^{-34} \text{ J s} Speed of light, c=3×108 m/sc = 3 \times 10^8 \text{ m/s}

  • Energy, E=3.03×10−19 JE = 3.03 \times 10^{-19} \text{ J}

Substituting the values: λ=(6.6×10−34 J s)(3×108 m/s)3.03×10−19 J\lambda = \frac{(6.6 \times 10^{-34} \text{ J s})(3 \times 10^8 \text{ m/s})}{3.03 \times 10^{-19} \text{ J}} λ=19.8×10−263.03×10−19 m\lambda = \frac{19.8 \times 10^{-26}}{3.03 \times 10^{-19}} \text{ m} λ≈6.534×10−7 m\lambda \approx 6.534 \times 10^{-7} \text{ m}

Converting to nanometers (1 nm=10−9 m1 \text{ nm} = 10^{-9} \text{ m}): λ=6.534×10−7×109 nm\lambda = 6.534 \times 10^{-7} \times 10^9 \text{ nm} λ=653.4 nm\lambda = 653.4 \text{ nm}

This matches Option 4.

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started