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NEET CHEMISTRYMedium

[Cu(NH3)4]2+[Cu(NH_3)_4]^{2+} reacts with HNO3HNO_3 in excess of water and gives:

A

Cu(OH)2Cu(OH)_2

B

Cu(NO3)2Cu(NO_3)_2

C

[Cu(H2O)4]2+[Cu(H_2O)_4]^{2+}

D

None of the above

Step-by-Step Solution

When a strong acid like nitric acid (HNO3HNO_3) is added to the tetraamminecopper(II) complex [Cu(NH3)4]2+[Cu(NH_3)_4]^{2+}, the acid protonates the basic ammonia (NH3NH_3) ligands to form ammonium ions (NH4+NH_4^+). This breaks the complex, releasing Cu2+Cu^{2+} ions into the aqueous solution. The Cu2+Cu^{2+} ions combine with the available nitrate (NO3NO_3^-) ions from the acid to form copper(II) nitrate. The reaction can be summarised as: [Cu(NH3)4]2++4HNO3ightarrowCu(NO3)2+4NH4++2NO3[Cu(NH_3)_4]^{2+} + 4HNO_3 ightarrow Cu(NO_3)_2 + 4NH_4^+ + 2NO_3^-. Therefore, aqueous Cu(NO3)2Cu(NO_3)_2 is obtained.

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