Back to Directory
NEET CHEMISTRYMedium

Which of the following options correctly describes the free expansion of an ideal gas under adiabatic conditions?

A

q0,ΔT=0,W=0q \neq 0, \Delta T = 0, W = 0

B

q=0,ΔT=0,W=0q = 0, \Delta T = 0, W = 0

C

q=0,ΔT<0,W0q = 0, \Delta T < 0, W \neq 0

D

q=0,ΔT0,W=0q = 0, \Delta T \neq 0, W = 0

Step-by-Step Solution

Free expansion of a gas occurs when it expands into a vacuum, where the external pressure (pextp_{ext}) is zero. The work done during expansion is given by the formula W=pextΔVW = -p_{ext} \Delta V. Since pext=0p_{ext} = 0, the work done W=0W = 0 . Since the condition is given as adiabatic, it means there is no heat exchange between the system and its surroundings, so q=0q = 0 . According to the First Law of Thermodynamics, the change in internal energy is given by ΔU=q+W\Delta U = q + W. Substituting the values, we get ΔU=0+0=0\Delta U = 0 + 0 = 0 . For an ideal gas, the change in internal energy is a function of temperature only (ΔU=nCvΔT\Delta U = nC_v\Delta T). Since ΔU=0\Delta U = 0, it implies that the change in temperature ΔT\Delta T is also 00 .

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started