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NEET CHEMISTRYEasy

Consider the following List-I and List-II:

List-I (Molecule) (a) PCl5PCl_{5} (b) SF6SF_{6} (c) BeCl2BeCl_{2} (d) NH3NH_{3}

List-II (Shape or geometry) (i) Trigonal planar (ii) Octahedral (iii) Linear (iv) Trigonal pyramidal

Identify the wrong match from the given pairs:

A

b

B

c

C

d

D

a

Step-by-Step Solution

To identify the wrong match, we evaluate the molecular geometry of each species based on VSEPR theory and hybridisation as described in the sources:

  1. PCl5PCl_{5} (Phosphorus pentachloride): Phosphorus has five valence electrons and forms five sigma bonds with chlorine atoms (AB5AB_{5} type). This results in sp3dsp^{3}d hybridisation and a trigonal bipyramidal geometry . List-II matches it with 'Trigonal planar', which is incorrect.
  2. SF6SF_{6} (Sulphur hexafluoride): Sulphur has six valence electrons and forms six sigma bonds with fluorine atoms (AB6AB_{6} type). This results in sp3d2sp^{3}d^{2} hybridisation and an octahedral geometry . This is a correct match.
  3. BeCl2BeCl_{2} (Beryllium chloride): Beryllium has two valence electrons and forms two sigma bonds (AB2AB_{2} type). This results in spsp hybridisation and a linear geometry . This is a correct match.
  4. NH3NH_{3} (Ammonia): Nitrogen has five valence electrons, forms three sigma bonds, and has one lone pair (AB3EAB_{3}E type). This results in sp3sp^{3} hybridisation and a trigonal pyramidal geometry . This is a correct match.

Since pair (a) is the only incorrect match, the correct choice is 'a'.

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