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Compound X on reaction with O3\text{O}_3 followed by Zn/H2O\text{Zn/H}_2\text{O} gives formaldehyde and 2-methyl propanal as products. The compound X is:

A

Pent-2-ene

B

3-Methylbut-1-ene

C

2-Methylbut-1-ene

D

2-Methylbut-2-ene

Step-by-Step Solution

Ozonolysis of an alkene involves the cleavage of the carbon-carbon double bond to form carbonyl compounds . To deduce the structure of the original alkene 'X', we can work backwards by removing the oxygen atoms from the given products (formaldehyde and 2-methylpropanal) and joining their respective carbonyl carbon atoms with a double bond.

  1. Structure of Formaldehyde: CH2=O\text{CH}_2\text{=O}
  2. Structure of 2-Methylpropanal: O=CH-CH(CH3)2\text{O=CH-CH(CH}_3)_2

Joining the double-bonded carbons yields the alkene: CH2=CH-CH(CH3)2\text{CH}_2\text{=CH-CH(CH}_3)_2. Numbering the principal carbon chain from the end nearer to the double bond gives the IUPAC name 3-Methylbut-1-ene .

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